2d - How to calculate corner positions/marks of a rotated/tilted rectangle?

I've got two elements, a 2D point and a rectangular area. The point represents the middle of that area. I also know the width and height of that area. And the area is tilted by 40° relative to the grid.

Now I'd like to calculate the absolute positions of each corner mark of that tilted area only using this data. Is that possible?

Answer

X = x*cos(θ) - y*sin(θ)
Y = x*sin(θ) + y*cos(θ)

This will give you the location of a point rotated θ degrees around the origin. Since the corners of the square are rotated around the center of the square and not the origin, a couple of steps need to be added to be able to use this formula. First you need to set the point relative to the origin. Then you can use the rotation formula. After the rotation you need to move it back relative to the center of the square.

// cx, cy - center of square coordinates
// x, y - coordinates of a corner point of the square
// theta is the angle of rotation

// translate point to origin
float tempX = x - cx;
float tempY = y - cy;


// now apply rotation
float rotatedX = tempX*cos(theta) - tempY*sin(theta);
float rotatedY = tempX*sin(theta) + tempY*cos(theta);

// translate back
x = rotatedX + cx;
y = rotatedY + cy;

Apply this to all 4 corners and you are done!